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10x^2-30=20x
We move all terms to the left:
10x^2-30-(20x)=0
a = 10; b = -20; c = -30;
Δ = b2-4ac
Δ = -202-4·10·(-30)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-40}{2*10}=\frac{-20}{20} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+40}{2*10}=\frac{60}{20} =3 $
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